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// The contents of this file are in the public domain. See LICENSE_FOR_EXAMPLE_PROGRAMS.txt
/*
This example demonstrates the usage of the numerical quadrature function
integrate_function_adapt_simp(). This function takes as input a single variable
function, the endpoints of a domain over which the function will be integrated, and a
tolerance parameter. It outputs an approximation of the integral of this function over
the specified domain. The algorithm is based on the adaptive Simpson method outlined in:
Numerical Integration method based on the adaptive Simpson method in
Gander, W. and W. Gautschi, "Adaptive Quadrature Revisited,"
BIT, Vol. 40, 2000, pp. 84-101
*/
#include <iostream>
#include <dlib/matrix.h>
#include <dlib/numeric_constants.h>
#include <dlib/numerical_integration.h>
using namespace std;
using namespace dlib;
// Here we the set of functions that we wish to integrate and comment in the domain of
// integration.
// x in [0,1]
double gg1(double x)
{
return pow(e,x);
}
// x in [0,1]
double gg2(double x)
{
return x*x;
}
// x in [0, pi]
double gg3(double x)
{
return 1/(x*x + cos(x)*cos(x));
}
// x in [-pi, pi]
double gg4(double x)
{
return sin(x);
}
// x in [0,2]
double gg5(double x)
{
return 1/(1 + x*x);
}
int main()
{
// We first define a tolerance parameter. Roughly speaking, a lower tolerance will
// result in a more accurate approximation of the true integral. However, there are
// instances where too small of a tolerance may yield a less accurate approximation
// than a larger tolerance. We recommend taking the tolerance to be in the
// [1e-10, 1e-8] region.
double tol = 1e-10;
// Here we compute the integrals of the five functions defined above using the same
// tolerance level for each.
double m1 = integrate_function_adapt_simp(&gg1, 0.0, 1.0, tol);
double m2 = integrate_function_adapt_simp(&gg2, 0.0, 1.0, tol);
double m3 = integrate_function_adapt_simp(&gg3, 0.0, pi, tol);
double m4 = integrate_function_adapt_simp(&gg4, -pi, pi, tol);
double m5 = integrate_function_adapt_simp(&gg5, 0.0, 2.0, tol);
// We finally print out the values of each of the approximated integrals to ten
// significant digits.
cout << "\nThe integral of exp(x) for x in [0,1] is " << std::setprecision(10) << m1 << endl;
cout << "The integral of x^2 for in [0,1] is " << std::setprecision(10) << m2 << endl;
cout << "The integral of 1/(x^2 + cos(x)^2) for in [0,pi] is " << std::setprecision(10) << m3 << endl;
cout << "The integral of sin(x) for in [-pi,pi] is " << std::setprecision(10) << m4 << endl;
cout << "The integral of 1/(1+x^2) for in [0,2] is " << std::setprecision(10) << m5 << endl;
cout << endl;
return 0;
}