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clarified docs
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We do this because Google protocol buffers are not
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We do this because Google protocol buffers are not
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<a href="https://developers.google.com/protocol-buffers/docs/techniques#streaming">self-delimiting</a>
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<a href="https://developers.google.com/protocol-buffers/docs/techniques#streaming">self-delimiting</a>
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on their own. This means that you can't write more than one protocol buffer object to an output stream unless you include some kind
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on their own. This means that you can't write more than one protocol buffer object to an output stream unless you include some kind
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of delimiter between the messages. So dlib takes care of this for you by encapsulating each protocol buffer message inside a serialized
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of delimiter between the messages.
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std::string object.
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So dlib takes care of this for you by prefixing each message with its length in bytes. The number
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of bytes is encoded using the same scheme that serialize(int,ostream) uses.
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</p>
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</p>
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</description>
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</description>
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@ -1008,8 +1009,9 @@
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We do this because Google protocol buffers are not
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We do this because Google protocol buffers are not
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<a href="https://developers.google.com/protocol-buffers/docs/techniques#streaming">self-delimiting</a>
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<a href="https://developers.google.com/protocol-buffers/docs/techniques#streaming">self-delimiting</a>
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on their own. This means that you can't write more than one protocol buffer object to an output stream unless you include some kind
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on their own. This means that you can't write more than one protocol buffer object to an output stream unless you include some kind
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of delimiter between the messages. So dlib takes care of this for you by encapsulating each protocol buffer message inside a serialized
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of delimiter between the messages.
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std::string object.
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So dlib takes care of this for you by prefixing each message with its length in bytes. The number
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of bytes is encoded using the same scheme that serialize(int,ostream) uses.
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</p>
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</p>
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</description>
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</description>
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