Simultaneous flushing stdout from several threads corrects the output. That is a bug, this is a bandaid for now.
git-svn-id: svn://svn.code.sf.net/p/nuttx/code/trunk@118 42af7a65-404d-4744-a932-0658087f49c3
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@ -1,5 +1,5 @@
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/********************************************************************************
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* dev_null.c
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* roundrobin.c
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*
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* Copyright (C) 2007 Gregory Nutt. All rights reserved.
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* Author: Gregory Nutt <spudmonkey@racsa.co.cr>
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@ -125,7 +125,6 @@ static void *sieve1(void *parameter)
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int i;
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printf("sieve1 started\n");
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fflush(stdout);
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for (i = 0; i < 1000; i++)
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{
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@ -133,7 +132,6 @@ static void *sieve1(void *parameter)
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}
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printf("sieve1 finished\n");
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fflush(stdout);
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pthread_exit(NULL);
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}
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@ -147,7 +145,6 @@ static void *sieve2(void *parameter)
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int i;
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printf("sieve2 started\n");
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fflush(stdout);
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for (i = 0; i < 1000; i++)
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{
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@ -155,7 +152,6 @@ static void *sieve2(void *parameter)
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}
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printf("sieve2 finished\n");
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fflush(stdout);
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pthread_exit(NULL);
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}
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@ -222,7 +218,6 @@ void rr_test(void)
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printf("rr_test: Waiting for sieves to complete -- this should take awhile\n");
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printf("rr_test: If RR scheduling is working, they should start and complete at\n");
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printf("rr_test: about the same time\n");
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fflush(stdout);
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pthread_join(sieve2_thread, &result);
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pthread_join(sieve1_thread, &result);
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