execl(): Fix bad logic in counting the number of arguments. This could never have worked. Noted by Pierre-noel Bouteville
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@ -1,7 +1,7 @@
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/****************************************************************************
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* libc/unistd/lib_execl.c
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*
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* Copyright (C) 2013 Gregory Nutt. All rights reserved.
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* Copyright (C) 2013, 2015 Gregory Nutt. All rights reserved.
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* Author: Gregory Nutt <gnutt@nuttx.org>
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*
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* Redistribution and use in source and binary forms, with or without
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@ -127,6 +127,7 @@
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int execl(FAR const char *path, ...)
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{
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FAR char **argv = (FAR char **)NULL;
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FAR char *arg;
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size_t nargs;
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va_list ap;
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int argc;
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@ -135,21 +136,29 @@ int execl(FAR const char *path, ...)
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/* Count the number of arguments */
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va_start(ap, path);
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for (nargs = 0, argc = 0; argv[argc]; argc++)
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nargs = 0;
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do
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{
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/* Increment the number of args. Here is a sanity check to prevent
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* running away with an unterminated argv[] list. MAX_EXECL_ARGS
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* should be sufficiently large that this never happens in normal
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* usage.
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*/
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/* Check if the next argument is present */
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if (++nargs > MAX_EXECL_ARGS)
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arg = va_arg(ap, FAR char *)
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if (arg)
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{
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set_errno(E2BIG);
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va_end(ap);
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return ERROR;
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/* Yes.. increment the number of arguments. Here is a sanity
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* check to prevent running away with an unterminated argv[] list.
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* MAX_EXECL_ARGS should be sufficiently large that this never
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* happens in normal usage.
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*/
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if (++nargs > MAX_EXECL_ARGS)
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{
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set_errno(E2BIG);
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va_end(ap);
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return ERROR;
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}
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}
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}
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while (arg);
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va_end(ap);
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