x86/softirq/64: Inline do_softirq_own_stack()
There is no reason to have this as a seperate function for a single caller. Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Reviewed-by: Kees Cook <keescook@chromium.org> Link: https://lore.kernel.org/r/20210210002513.382806685@linutronix.de
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@ -194,7 +194,7 @@
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* interrupts are pending to be processed. The interrupt stack cannot be in
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* use here.
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*/
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#define run_softirq_on_irqstack() \
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#define do_softirq_own_stack() \
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{ \
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__this_cpu_write(hardirq_stack_inuse, true); \
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call_on_irqstack(__do_softirq, ASM_CALL_SOFTIRQ); \
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@ -202,7 +202,6 @@
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}
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#else /* CONFIG_X86_64 */
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/* System vector handlers always run on the stack they interrupted. */
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#define run_sysvec_on_irqstack_cond(func, regs) \
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{ \
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@ -0,0 +1,11 @@
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/* SPDX-License-Identifier: GPL-2.0 */
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#ifndef _ASM_X86_SOFTIRQ_STACK_H
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#define _ASM_X86_SOFTIRQ_STACK_H
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#ifdef CONFIG_X86_64
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# include <asm/irq_stack.h>
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#else
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# include <asm-generic/softirq_stack.h>
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#endif
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#endif
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@ -74,8 +74,3 @@ int irq_init_percpu_irqstack(unsigned int cpu)
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return 0;
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return map_irq_stack(cpu);
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}
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void do_softirq_own_stack(void)
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{
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run_softirq_on_irqstack();
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}
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