acrn-hypervisor/hypervisor/lib/string.c

467 lines
8.6 KiB
C

/*
* Copyright (C) 2018 Intel Corporation.
* SPDX-License-Identifier: BSD-3-Clause
*/
#include <hypervisor.h>
#define ULONG_MAX ((uint64_t)(~0UL)) /* 0xFFFFFFFF */
#define LONG_MAX (ULONG_MAX >> 1U) /* 0x7FFFFFFF */
#define LONG_MIN (~LONG_MAX) /* 0x80000000 */
static inline bool is_space(char c)
{
return ((c == ' ') || (c == '\t'));
}
/*
* Convert a string to a long integer - decimal support only.
*/
long strtol_deci(const char *nptr)
{
const char *s = nptr;
char c;
uint64_t acc, cutoff, cutlim;
int neg = 0, any;
uint64_t base = 10UL;
/*
* Skip white space and pick up leading +/- sign if any.
*/
do {
c = *s;
s++;
} while (is_space(c));
if (c == '-') {
neg = 1;
c = *s;
s++;
} else if (c == '+') {
c = *s;
s++;
} else {
/* No sign character. */
}
/*
* Compute the cutoff value between legal numbers and illegal
* numbers. That is the largest legal value, divided by the
* base. An input number that is greater than this value, if
* followed by a legal input character, is too big. One that
* is equal to this value may be valid or not; the limit
* between valid and invalid numbers is then based on the last
* digit. For instance, if the range for longs is
* [-2147483648..2147483647] and the input base is 10,
* cutoff will be set to 214748364 and cutlim to either
* 7 (neg==0) or 8 (neg==1), meaning that if we have accumulated
* a value > 214748364, or equal but the next digit is > 7 (or 8),
* the number is too big, and we will return a range error.
*
* Set any if any `digits' consumed; make it negative to indicate
* overflow.
*/
cutoff = (neg != 0) ? LONG_MIN : LONG_MAX;
cutlim = cutoff % base;
cutoff /= base;
acc = 0UL;
any = 0;
while ((c >= '0') && (c <= '9')) {
c -= '0';
if ((acc > cutoff) ||
((acc == cutoff) && ((uint64_t)c > cutlim))) {
any = -1;
break;
} else {
acc *= base;
acc += c;
}
c = *s;
s++;
}
if (any < 0) {
acc = (neg != 0) ? LONG_MIN : LONG_MAX;
} else if (neg != 0) {
acc = ~acc + 1UL;
} else {
/* There is no overflow and no leading '-' exists. In such case
* acc already holds the right number. No action required. */
}
return (long)acc;
}
/*
* Convert a string to an uint64_t integer - hexadecimal support only.
*/
uint64_t strtoul_hex(const char *nptr)
{
const char *s = nptr;
char c;
uint64_t acc, cutoff, cutlim;
uint64_t base = 16UL;
int any;
/*
* See strtol for comments as to the logic used.
*/
do {
c = *s;
s++;
} while (is_space(c));
if ((c == '0') && ((*s == 'x') || (*s == 'X'))) {
c = s[1];
s += 2;
}
cutoff = ULONG_MAX / base;
cutlim = ULONG_MAX % base;
acc = 0UL;
any = 0;
do {
if ((c >= '0') && (c <= '9')) {
c -= '0';
} else if ((c >= 'A') && (c <= 'F')) {
c -= 'A' - 10;
} else if ((c >= 'a') && (c <= 'f')) {
c -= 'a' - 10;
} else {
break;
}
if ((acc > cutoff) ||
((acc == cutoff) && ((uint64_t)c > cutlim))) {
any = -1;
break;
} else {
acc *= base;
acc += c;
}
c = *s;
s++;
} while (true);
if (any < 0) {
acc = ULONG_MAX;
}
return acc;
}
int atoi(const char *str)
{
return (int)strtol_deci(str);
}
char *strchr(char *s_arg, char ch)
{
char *s = s_arg;
while ((*s != '\0') && (*s != ch)) {
++s;
}
return ((*s) != '\0') ? s : NULL;
}
/**
*strcpy_s
*
* description:
* This function copies the string pointed to by s to a buffer
* pointed by d.
*
* input:
* d pointer to dest buffer.
*
* dmax maximum length of dest buffer
*
* s pointer to the source string
*
* return value:
* dest pointer to dest string if string is copied
* successfully,or else return null.
*
* notes:
* 1) both d and s shall not be null pointers.
* 2) dmax shall not 0.
*/
char *strcpy_s(char *d_arg, size_t dmax, const char *s_arg)
{
char *d = d_arg;
const char *s = s_arg;
char *dest_base;
size_t dest_avail;
uint64_t overlap_guard;
if ((s == NULL) || (d == NULL) || (dmax == 0U)) {
pr_err("%s: invalid src, dest buffer or length.", __func__);
return NULL;
}
if (s == d) {
return d;
}
overlap_guard = (uint64_t)((d > s) ? (d - s - 1) : (s - d - 1));
dest_avail = dmax;
dest_base = d;
while (dest_avail > 0U) {
if (overlap_guard == 0U) {
pr_err("%s: overlap happened.", __func__);
d--;
*d = '\0';
return NULL;
}
*d = *s;
if (*d == '\0') {
return dest_base;
}
d++;
s++;
dest_avail--;
overlap_guard--;
}
pr_err("%s: dest buffer has no enough space.", __func__);
/*
* to avoid a string that is not
* null-terminated in dest buffer
*/
dest_base[dmax - 1] = '\0';
return NULL;
}
/*
* strncpy_s
*
* description:
* This function copies maximum 'slen'characters from string pointed
* by s to a buffer pointed by d.
*
* input:
* d pointer to dest buffer.
*
* dmax maximum length of dest buffer.
*
* s pointer to the source string.
*
* slen the maximum number of characters to copy from source
* string.
*
* return value:
* dest pointer to dest string if source string is copied
* successfully, or else return null.
*
* notes:
* 1) both dmax and slen should not be 0.
* 2) both d and s should not be null pointers.
* 3) will assert() if overlap happens or dest buffer has no
* enough space.
*/
char *strncpy_s(char *d_arg, size_t dmax, const char *s_arg, size_t slen_arg)
{
const char *s = s_arg;
char *d = d_arg;
char *dest_base;
size_t dest_avail;
uint64_t overlap_guard;
size_t slen = slen_arg;
if ((d == NULL) || (s == NULL)) {
pr_err("%s: invlaid src or dest buffer", __func__);
return NULL;
}
if ((dmax == 0U) || (slen == 0U)) {
pr_err("%s: invlaid length of src or dest buffer", __func__);
return NULL;
}
if (d == s) {
return d;
}
overlap_guard = (uint64_t)((d > s) ? (d - s - 1) : (s - d - 1));
dest_base = d;
dest_avail = dmax;
while (dest_avail > 0U) {
if (overlap_guard == 0U) {
pr_err("%s: overlap happened.", __func__);
d--;
*d = '\0';
return NULL;
}
if (slen == 0U) {
*d = '\0';
return dest_base;
}
*d = *s;
if (*d == '\0') {
return dest_base;
}
d++;
s++;
slen--;
dest_avail--;
overlap_guard--;
}
pr_err("%s: dest buffer has no enough space.", __func__);
/*
* to avoid a string that is not
* null-terminated in dest buffer
*/
dest_base[dmax - 1] = '\0';
return NULL;
}
/**
*
* strnlen_s
*
* description:
* The function calculates the length of the string pointed
* to by str.
*
*
* input:
* str pointer to the null-terminated string to be examined.
*
* dmax maximum number of characer to examine.
*
* return value:
* string length, excluding the null character.
* will return 0 if str is null.
*/
size_t strnlen_s(const char *str_arg, size_t maxlen_arg)
{
const char *str = str_arg;
size_t maxlen = maxlen_arg;
size_t count;
if (str == NULL) {
return 0;
}
count = 0U;
while ((*str) != '\0') {
if (maxlen == 0U) {
break;
}
count++;
maxlen--;
str++;
}
return count;
}
int strcmp(const char *s1_arg, const char *s2_arg)
{
const char *s1 = s1_arg;
const char *s2 = s2_arg;
while (((*s1) != '\0') && ((*s2) != '\0') && ((*s1) == (*s2))) {
s1++;
s2++;
}
return *s1 - *s2;
}
int strncmp(const char *s1_arg, const char *s2_arg, size_t n_arg)
{
const char *s1 = s1_arg;
const char *s2 = s2_arg;
size_t n = n_arg;
while (((n - 1) != 0U) && ((*s1) != '\0') && ((*s2) != '\0')
&& ((*s1) == (*s2))) {
s1++;
s2++;
n--;
}
return *s1 - *s2;
}
/*
* strstr_s
*
* description:
* Search str2 in str1
*
* input:
* str1 pointer to string to be searched for the substring.
*
* maxlen1 maximum length of str1.
*
* str2 pointer to the sub-string.
*
* maxlen2 maximum length of str2.
*
* return value:
* Pointer to the first occurrence of str2 in str1,
* or return null if not found.
*/
char *strstr_s (const char *str1, size_t maxlen1,
const char *str2, size_t maxlen2)
{
size_t len1, len2;
size_t i;
if ((str1 == NULL) || (str2 == NULL)) {
return NULL;
}
if ((maxlen1 == 0U) || (maxlen2 == 0U)) {
return NULL;
}
len1 = strnlen_s(str1, maxlen1);
len2 = strnlen_s(str2, maxlen2);
if (len1 == 0U) {
return NULL;
}
/*
* str2 points to a string with zero length, or
* str2 equals str1, return str1
*/
if (len2 == 0U || str1 == str2) {
return (char *)str1;
}
while (len1 >= len2) {
for (i=0U; i<len2; i++) {
if (str1[i] != str2[i]) {
break;
}
}
if (i == len2) {
return (char *)str1;
}
str1++;
len1--;
}
/*
* substring was not found, return NULL
*/
return NULL;
}