467 lines
8.6 KiB
C
467 lines
8.6 KiB
C
/*
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* Copyright (C) 2018 Intel Corporation.
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* SPDX-License-Identifier: BSD-3-Clause
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*/
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#include <hypervisor.h>
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#define ULONG_MAX ((uint64_t)(~0UL)) /* 0xFFFFFFFF */
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#define LONG_MAX (ULONG_MAX >> 1U) /* 0x7FFFFFFF */
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#define LONG_MIN (~LONG_MAX) /* 0x80000000 */
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static inline bool is_space(char c)
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{
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return ((c == ' ') || (c == '\t'));
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}
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/*
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* Convert a string to a long integer - decimal support only.
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*/
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long strtol_deci(const char *nptr)
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{
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const char *s = nptr;
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char c;
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uint64_t acc, cutoff, cutlim;
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int neg = 0, any;
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uint64_t base = 10UL;
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/*
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* Skip white space and pick up leading +/- sign if any.
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*/
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do {
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c = *s;
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s++;
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} while (is_space(c));
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if (c == '-') {
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neg = 1;
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c = *s;
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s++;
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} else if (c == '+') {
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c = *s;
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s++;
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} else {
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/* No sign character. */
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}
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/*
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* Compute the cutoff value between legal numbers and illegal
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* numbers. That is the largest legal value, divided by the
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* base. An input number that is greater than this value, if
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* followed by a legal input character, is too big. One that
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* is equal to this value may be valid or not; the limit
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* between valid and invalid numbers is then based on the last
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* digit. For instance, if the range for longs is
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* [-2147483648..2147483647] and the input base is 10,
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* cutoff will be set to 214748364 and cutlim to either
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* 7 (neg==0) or 8 (neg==1), meaning that if we have accumulated
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* a value > 214748364, or equal but the next digit is > 7 (or 8),
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* the number is too big, and we will return a range error.
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*
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* Set any if any `digits' consumed; make it negative to indicate
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* overflow.
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*/
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cutoff = (neg != 0) ? LONG_MIN : LONG_MAX;
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cutlim = cutoff % base;
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cutoff /= base;
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acc = 0UL;
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any = 0;
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while ((c >= '0') && (c <= '9')) {
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c -= '0';
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if ((acc > cutoff) ||
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((acc == cutoff) && ((uint64_t)c > cutlim))) {
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any = -1;
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break;
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} else {
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acc *= base;
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acc += c;
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}
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c = *s;
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s++;
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}
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if (any < 0) {
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acc = (neg != 0) ? LONG_MIN : LONG_MAX;
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} else if (neg != 0) {
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acc = ~acc + 1UL;
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} else {
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/* There is no overflow and no leading '-' exists. In such case
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* acc already holds the right number. No action required. */
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}
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return (long)acc;
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}
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/*
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* Convert a string to an uint64_t integer - hexadecimal support only.
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*/
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uint64_t strtoul_hex(const char *nptr)
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{
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const char *s = nptr;
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char c;
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uint64_t acc, cutoff, cutlim;
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uint64_t base = 16UL;
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int any;
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/*
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* See strtol for comments as to the logic used.
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*/
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do {
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c = *s;
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s++;
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} while (is_space(c));
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if ((c == '0') && ((*s == 'x') || (*s == 'X'))) {
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c = s[1];
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s += 2;
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}
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cutoff = ULONG_MAX / base;
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cutlim = ULONG_MAX % base;
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acc = 0UL;
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any = 0;
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do {
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if ((c >= '0') && (c <= '9')) {
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c -= '0';
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} else if ((c >= 'A') && (c <= 'F')) {
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c -= 'A' - 10;
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} else if ((c >= 'a') && (c <= 'f')) {
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c -= 'a' - 10;
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} else {
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break;
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}
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if ((acc > cutoff) ||
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((acc == cutoff) && ((uint64_t)c > cutlim))) {
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any = -1;
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break;
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} else {
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acc *= base;
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acc += c;
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}
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c = *s;
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s++;
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} while (true);
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if (any < 0) {
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acc = ULONG_MAX;
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}
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return acc;
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}
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int atoi(const char *str)
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{
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return (int)strtol_deci(str);
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}
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char *strchr(char *s_arg, char ch)
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{
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char *s = s_arg;
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while ((*s != '\0') && (*s != ch)) {
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++s;
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}
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return ((*s) != '\0') ? s : NULL;
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}
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/**
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*strcpy_s
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*
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* description:
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* This function copies the string pointed to by s to a buffer
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* pointed by d.
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*
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* input:
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* d pointer to dest buffer.
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*
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* dmax maximum length of dest buffer
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*
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* s pointer to the source string
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*
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* return value:
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* dest pointer to dest string if string is copied
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* successfully,or else return null.
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*
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* notes:
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* 1) both d and s shall not be null pointers.
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* 2) dmax shall not 0.
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*/
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char *strcpy_s(char *d_arg, size_t dmax, const char *s_arg)
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{
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char *d = d_arg;
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const char *s = s_arg;
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char *dest_base;
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size_t dest_avail;
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uint64_t overlap_guard;
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if ((s == NULL) || (d == NULL) || (dmax == 0U)) {
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pr_err("%s: invalid src, dest buffer or length.", __func__);
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return NULL;
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}
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if (s == d) {
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return d;
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}
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overlap_guard = (uint64_t)((d > s) ? (d - s - 1) : (s - d - 1));
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dest_avail = dmax;
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dest_base = d;
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while (dest_avail > 0U) {
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if (overlap_guard == 0U) {
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pr_err("%s: overlap happened.", __func__);
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d--;
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*d = '\0';
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return NULL;
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}
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*d = *s;
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if (*d == '\0') {
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return dest_base;
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}
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d++;
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s++;
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dest_avail--;
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overlap_guard--;
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}
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pr_err("%s: dest buffer has no enough space.", __func__);
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/*
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* to avoid a string that is not
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* null-terminated in dest buffer
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*/
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dest_base[dmax - 1] = '\0';
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return NULL;
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}
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/*
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* strncpy_s
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*
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* description:
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* This function copies maximum 'slen'characters from string pointed
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* by s to a buffer pointed by d.
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*
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* input:
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* d pointer to dest buffer.
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*
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* dmax maximum length of dest buffer.
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*
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* s pointer to the source string.
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*
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* slen the maximum number of characters to copy from source
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* string.
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*
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* return value:
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* dest pointer to dest string if source string is copied
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* successfully, or else return null.
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*
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* notes:
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* 1) both dmax and slen should not be 0.
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* 2) both d and s should not be null pointers.
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* 3) will assert() if overlap happens or dest buffer has no
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* enough space.
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*/
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char *strncpy_s(char *d_arg, size_t dmax, const char *s_arg, size_t slen_arg)
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{
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const char *s = s_arg;
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char *d = d_arg;
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char *dest_base;
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size_t dest_avail;
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uint64_t overlap_guard;
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size_t slen = slen_arg;
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if ((d == NULL) || (s == NULL)) {
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pr_err("%s: invlaid src or dest buffer", __func__);
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return NULL;
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}
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if ((dmax == 0U) || (slen == 0U)) {
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pr_err("%s: invlaid length of src or dest buffer", __func__);
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return NULL;
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}
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if (d == s) {
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return d;
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}
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overlap_guard = (uint64_t)((d > s) ? (d - s - 1) : (s - d - 1));
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dest_base = d;
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dest_avail = dmax;
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while (dest_avail > 0U) {
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if (overlap_guard == 0U) {
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pr_err("%s: overlap happened.", __func__);
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d--;
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*d = '\0';
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return NULL;
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}
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if (slen == 0U) {
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*d = '\0';
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return dest_base;
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}
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*d = *s;
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if (*d == '\0') {
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return dest_base;
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}
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d++;
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s++;
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slen--;
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dest_avail--;
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overlap_guard--;
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}
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pr_err("%s: dest buffer has no enough space.", __func__);
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/*
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* to avoid a string that is not
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* null-terminated in dest buffer
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*/
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dest_base[dmax - 1] = '\0';
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return NULL;
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}
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/**
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*
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* strnlen_s
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*
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* description:
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* The function calculates the length of the string pointed
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* to by str.
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*
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*
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* input:
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* str pointer to the null-terminated string to be examined.
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*
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* dmax maximum number of characer to examine.
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*
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* return value:
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* string length, excluding the null character.
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* will return 0 if str is null.
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*/
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size_t strnlen_s(const char *str_arg, size_t maxlen_arg)
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{
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const char *str = str_arg;
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size_t maxlen = maxlen_arg;
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size_t count;
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if (str == NULL) {
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return 0;
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}
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count = 0U;
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while ((*str) != '\0') {
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if (maxlen == 0U) {
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break;
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}
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count++;
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maxlen--;
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str++;
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}
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return count;
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}
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int strcmp(const char *s1_arg, const char *s2_arg)
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{
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const char *s1 = s1_arg;
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const char *s2 = s2_arg;
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while (((*s1) != '\0') && ((*s2) != '\0') && ((*s1) == (*s2))) {
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s1++;
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s2++;
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}
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return *s1 - *s2;
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}
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int strncmp(const char *s1_arg, const char *s2_arg, size_t n_arg)
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{
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const char *s1 = s1_arg;
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const char *s2 = s2_arg;
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size_t n = n_arg;
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while (((n - 1) != 0U) && ((*s1) != '\0') && ((*s2) != '\0')
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&& ((*s1) == (*s2))) {
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s1++;
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s2++;
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n--;
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}
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return *s1 - *s2;
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}
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/*
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* strstr_s
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*
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* description:
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* Search str2 in str1
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*
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* input:
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* str1 pointer to string to be searched for the substring.
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*
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* maxlen1 maximum length of str1.
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*
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* str2 pointer to the sub-string.
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*
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* maxlen2 maximum length of str2.
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*
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* return value:
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* Pointer to the first occurrence of str2 in str1,
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* or return null if not found.
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*/
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char *strstr_s (const char *str1, size_t maxlen1,
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const char *str2, size_t maxlen2)
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{
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size_t len1, len2;
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size_t i;
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if ((str1 == NULL) || (str2 == NULL)) {
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return NULL;
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}
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if ((maxlen1 == 0U) || (maxlen2 == 0U)) {
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return NULL;
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}
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len1 = strnlen_s(str1, maxlen1);
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len2 = strnlen_s(str2, maxlen2);
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if (len1 == 0U) {
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return NULL;
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}
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/*
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* str2 points to a string with zero length, or
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* str2 equals str1, return str1
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*/
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if (len2 == 0U || str1 == str2) {
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return (char *)str1;
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}
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while (len1 >= len2) {
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for (i=0U; i<len2; i++) {
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if (str1[i] != str2[i]) {
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break;
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}
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}
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if (i == len2) {
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return (char *)str1;
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}
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str1++;
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len1--;
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}
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/*
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* substring was not found, return NULL
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*/
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return NULL;
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}
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