hv: ignore the initialization of vdevs whose vbdf is unassigned
if device configuration vbdf is unassigned, then the corresponding vdev will not be initialized, instead, the vdev will be initialized by device model through hypercall. Tracked-On: #4853 Signed-off-by: Yuan Liu <yuan1.liu@intel.com> Acked-by: Eddie Dong <eddie.dong@intel.com>
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@ -653,7 +653,10 @@ static void vpci_init_vdevs(struct acrn_vm *vm)
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const struct acrn_vm_config *vm_config = get_vm_config(vpci2vm(vpci)->vm_id);
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for (idx = 0U; idx < vm_config->pci_dev_num; idx++) {
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(void)vpci_init_vdev(vpci, &vm_config->pci_devs[idx], NULL);
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/* the vdev whose vBDF is unassigned will be created by hypercall */
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if ((!is_postlaunched_vm(vm)) || (vm_config->pci_devs[idx].vbdf.value != UNASSIGNED_VBDF)) {
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(void)vpci_init_vdev(vpci, &vm_config->pci_devs[idx], NULL);
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}
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}
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}
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